Puzzle # 1
When I was 6, my sister was half my age. Now I’m 50, how old is she?
Click to See Solution:
Answer: 47
Explanation:
When I was 6, my sister was half my age.
This means my sister was 6 ÷ 2 = 3 years old at that time.
From this, we can deduce that my sister is 3 years younger than me.
Now, since I am 50, my sister’s age is 50 – 3 = 47.
NOTE: The key to solving this puzzle is recognizing that the age difference between you and your sister remains constant over time. In this case, the 3-year difference that was established when you were 6 still applies when you are 50. By subtracting this constant difference from your current age, you find your sister’s age.
Puzzle # 2
When I was 4 years old, my sister’s age was twice mine. I am 25 years old now. How old is my sister?
Click to See Solution:
Answer: 29 Years
Explanation:
When I was 4, my sister was twice my age, meaning she was 4 × 2 = 8 years old.
The difference in age between us is 8 – 4 = 4 years.
Now that I am 25, my sister is 4 years older than me. So, her current age is 25 + 4 = 29.
Puzzle #3
Mr. Smith said to his son, “I was one-third of your present age when you were born.” If the present age of Mr. Smith is 48 years, find the present age of the son.
Click to See Solution:
Answer: 36 years.
Explanation:
Let the present age of the son be S
According to Mr. Smith, he was one-third of the son’s current age when the son was born. This means that Mr. Smith’s age at that time was S/3
Since the son was born S years ago, we can determine Mr. Smith’s age at that time. Given that Mr. Smith is currently 48 years old, his age when the son was born was: 48-S
Now, we can set up the equation based on the information provided:
48-S = S/3 (i.e when the son was born)
Now let’s solve the equation:
48-S = S/3
48= S+S/3
48 =4S/3
S =144/3
S= 36
Thus, the present age of the son is 36 years.
Puzzle #4
Lila and Maya are two sisters. Right now, Lila is two-fifths of her older sister Maya’s age. Two years from now, Lila will be half of Maya’s age at that time. Two years ago, Lila was only one-fourth of Maya’s age at that time.
How old are Lila and Maya now?
Click to See Solution:
Answer: Lila is 4 years old while Maya is 10 years
Explanation:
Let Lila’s age be L and Maya’s age be M
From the statement, “Lila is two-fifths of her older sister Maya’s age”, we can form the equation: 2/5L = M
And from the statement, “Two years from now, Lila will be half of Maya’s age at that time”, we can form the equation: L+2 =1/2(M+2)
The above equation can also be written as: 2 (L+2) = M+2
And finally from the statement, “Two years ago, Lila was only one-fourth of Maya’s age at that time”, we can form the equation: L-2 =1/4 (M-2)
The equation can also be written as: 4(L-2) = M-2
So now we have two equations, which we can solve to find the value of L and M:
2 (L+2) = M+2…..equation (I)
4(L-2) = M-2………..equation (II)
Proceed as follows:
2L + 4 = M+2
4L -8 = M-2
2L – M = -2
4L- M = 6
2L = 8
L = 4
Finally substitute 4 in 2L – M = -2 OR 4L- M = 6 to find M
M = 10
Thus, Lila is 4 years old while Maya is 10 years
Puzzle # 5
I have twice the age you had when I had the age you have.
When you’ll have the age I have, together we will have 63 years.
How old are we (individually)?
Click to See Solution:
Answer: My current age is 28 years and yours is 21 years
Explanation:
To solve this puzzle, you need to think about 3 different timelines, the past, now, and the future, and form equations based on these timelines as follows:
Let:
- P: My age in the past.
- P’: Your age in the past.
- N: My age now (current age).
- N’: Your age now (current age).
- F: My age in the future.
- F’: Your age in the future.
The statement, “I have twice the age you had when I had the age you have” means that my current age (N) is twice your age in the past (P’). So, N = 2P’.
And the statement, “When you’ll have the age I have, together we will have 63 years” tells us that in the future, when you reach my current age (F’ = N), together we’ll be 63 years old. So: F’ + F =63
Because we’ve established that N = 2P’, itmeans F’ = N = 2P’.
There is part of statement 1 that is also crucial: ….WHEN I HAD THE AGE YOU HAVE
The part/phrase “when I had the age you have” means that in the past, I was the age you are now. This makes P = N’, because P (my age at that time) is exactly the same as your current age, N’. In other words, we are saying that the age I had at some point in the past (P) is equal to your present age (N’).
So far, we have these equations:
- N = 2P’
- F’ = N = 2P’
- P = N’
- F’ + F =63
I hope we’re on the same page up to this point. Great! Let’s move on…
Since time moves the same for both of us, the difference between our ages never changes. So your future age minus your current age should be equal to my future age minus current age. So we can have:
F′−N′ = F−N
…which can also be written as F –F’ = N –N’ to mean thatthe number of years between our future ages is the same as the number of years between our current ages.
Going by the same analogy, the difference between your current age and your past age should also be equal to the difference between my current age and my past age. So, we can also have:
N` – P` = N – P.
Now we have 6 equations:
- N = 2P’
- F’ = N = 2P’
- P = N’
- F’ + F =63
- F′−N′ = F−N
- N` – P` = N – P.
Let’s use them to solve the puzzle….
F’- N’ = F- N
but from equation (II) F’ = N= 2P’
So, 2P’- N’ = F = 2P’
and from equation (III), P = N’
Which means 2P’- P = F -2P’……………………….(VII)
but F = 63 – F’ (from equation (IV)
which can also be written as: F = 63 – 2P'(because F’ = N = 2p’)
Equation (VII) then becomes: 2P’-P = 63- 2P’ – 2P’, which we can break further as follows:
2P’ + 2P’ + 2P’ = 63 + P
6P’ = 63 + P
and P = 63 – 6P’…………..(VIII)
Let’s now focus on equation (VI): N’- P’ = N – P
from equation (III), we know that P = N’
so (VI) becomes P – P’ = N – P
but again N = 2P’
so P- P’ = 2P’- P
and by putting like terms together, we have: 2P = 3P’
and we can say that P = 3/2P’
In equation (VIII), we had: P = P = 3/2P’
so, 3/2P’ = P = 3/2P’
3P’ = 126 -6P’
9P’ = 126
P’= 14
Thus, your past age = 14 years
From equation (I), my current age = 2x 14 = 28 years
In equation (II), we had F’ = N = 2P’, which implies that your future age is also 28 years
Since when my future age is added to your future age sums we get a total of 63 years, (i.e F + F’ = 63), it means:
F + 28 (your future age) = 63
So F (my future age) = 63-28 = 35 years
If my current age is 28 years and my future is 35 years, it means F -N = 7
So, from equation (V), we can get your current age as follows:
F’ – N’ = F – N = 7
28 – N’ = 7
and N’ = 28-7 = 21
So my current age is 28 years and yours is 21 years.
About Age Puzzles
What are Age Puzzles?
Age puzzles are an interesting category of brain teasers that challenge your ability to deduce a person’s age (or determine when they were a certain age) through a series of modest clues.
They typically present you with a set of facts or relationships between ages that you must unravel to find a person’s current age or an age they were at a specific time.
These puzzles, often found in math books, logic games, and even in real-life riddles, require keen reasoning, a good grasp of numbers, and attention to detail.
While the clues in some age puzzles may seem random or convoluted at first, the satisfaction of arriving at the correct answer makes these puzzles irresistible for puzzle enthusiasts.
Why Are Age Puzzles So Popular?
Age puzzles are widely loved for their simplicity and elegance. Unlike many math problems, they require minimal technical knowledge—only basic arithmetic and algebra—but reward logical thinking.
These puzzles are also engaging because they present a relatable challenge: figuring out someone’s age is something we do regularly in life, but here it’s disguised in a more puzzling form.
Age puzzles are also versatile and can be made as easy or as complex as you like, making them suitable for a wide audience, from children learning math to adults looking for a mental workout.
How to Solve Age Puzzles
Age puzzles follow a logical path, which means that breaking them down step-by-step is the key to solving them. Here are some tips for tackling them:
- Translate the Clues into Equations: Age puzzles often describe relationships in words, so your first step is to express these relationships mathematically. For example, if someone is said to be “three years younger,” subtract three from the person’s age. If someone is “twice as old,” multiply by two.
- Work with Variables: Assign variables to the unknowns. For instance, if you’re solving for a person’s current age, let “x” represent that unknown. Then, create an equation that represents the relationships described in the puzzle.
- Use Time Shifts: Puzzles often refer to different points in time (e.g., “five years ago” or “in ten years”). Translate these time shifts into algebraic terms. If you are given someone’s age five years ago, represent that as “x – 5,” where “x” is their current age.
- Solve Systematically: Once you have the equations in place, solve them using basic algebra. Some puzzles involve more than one unknown (like two people’s ages), so you might need to solve a system of equations.
As you can see from the examples above, age puzzles can range from simple to quite complex, making them a timeless classic in the world of brain teasers. They challenge your reasoning, require creative thinking, and may sometimes call for a bit of arithmetic to piece together the clues. But in the end, they reward you with the satisfaction of cracking a well-crafted puzzle. So, the next time you encounter an age puzzle, embrace the challenge and enjoy the process of working your way to the solution!